You forgot * before pointer variable(before q1 variable)

I was thinking on the same but I am really suprised that it provides clean compile…

VCsala wrote:

I was thinking on the same but I am really suprised that it provides clean compile…

Me too, I tested it just. My compiler said:

conversion from ‘QListWidgetItem*’ to non-scalar type ‘QListWidgetItem’ requested

i forgot to put a * there,i actually put it in my program,missed it out here..

it is

edit: Code highlighting / Vass

It is a good idea (at least for the next time) to use ‘@’ around your code which makes syntax highlighted and more readable.

endla.ravi wrote:

ui->listWidgetItem->addItem(q1);

Is this correct (listWidgetItem or listWidget)?

Show more code, please.
I don’t understand, what is i  , what is list, why you set parent list, but adding item to ui->listWidget

I think this should look something like this:

And, according to the documentation, this will add the item to the list too, so it is not required to call the addItem.

If you have a sorted list, the above line has an undeterministic behaviour. In this case set the second paramater (parent) of the constructor to 0 and use ui->listWidget->insertItem(…) to insert the new item.

@all,thanQ..

I sorted out the problem..

Maybe it is a good idea to share what was the issue and how you have solved it.